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## Algebra Level 1 Test 1

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*Algebra Level 1 Test 1*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

P is the prime number, where P is ≥5, therefore ( P-1 )( P+1 ) is always divisible by

12 | |

24 | |

6 | |

48 |

Question 1 Explanation:

Answer is 24
The easiest approach is to consider the value of P as 5, 7, 11, 13.
As prime numbers are of the form, is either 6k+1 or 6k-1 hence the number is always divisible by 24

Question 2 |

( 5

^{25})^{35}=5^{x}. Find the Value of X60 | |

875 | |

35 ^{25} | |

25 ^{35} |

Question 2 Explanation:

As we know (a

^{m})^{n }= a^{mn}Hence Value of x = 25*35 = 875Question 3 |

( P+Q )

^{2}= 196, PQ = 48**Find the value of P****+ Q**^{2}^{2}100 | |

50 | |

148 | |

52 |

Question 3 Explanation:

(p + q)

^{2}= p^{2}+ 2pq + q^{2}Hence P**+ Q**^{2}**196- 2*48 = 100**^{2}=Question 4 |

( P+Q )

^{2}= 676, PQ = 160 Find the value of P**- Q**^{2}^{2}376 | |

96 | |

156 | |

36 |

Question 4 Explanation:

(P + Q)

^{2}= P^{2}+ 2PQ + Q^{2}(P - Q)^{2}= P^{2}– 2PQ + Q^{2}P+Q = 26 ; P-Q= 6 P= 16 Q= 10 hence P**- Q**^{2}**256- 100 = 156**^{2}=Question 5 |

3

^{24}/ 3^{2}=3^{x}. Find the Value of X12 | |

22 | |

24 | |

√24 |

Question 5 Explanation:

As we know a

^{m}/ a^{n }= a^{m-n}Hence the answer should be = 24-2 = 22 Once you are finished, click the button below. Any items you have not completed will be marked incorrect.

There are 5 questions to complete.

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