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## Arithmetic: Partnership Test-4

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Question 1 |

Three partners invested capitals in the ratio 2:7:9.The time period for which each of them invested was in the ratio of the reciprocals of the amount invested .Find the share of the partner who brought in the highest capital, if the profit is Rs. 1080.

Rs. 120 | |

Rs. 360 | |

Rs. 540 | |

Rs. 420 |

Question 1 Explanation:

Ratio of the investments = 2:7:9

Since the time is reciprocal so the ratio will be = Â½ : 1/7 : 1/9

Therefore the ratio of investment = 2 x 1/2 : 7 x 1/7 : 9 x 1/9 = 1:1:1

Therefore share of each of the partner

= 1/3 x 1080 = Rs. 360

Since the time is reciprocal so the ratio will be = Â½ : 1/7 : 1/9

Therefore the ratio of investment = 2 x 1/2 : 7 x 1/7 : 9 x 1/9 = 1:1:1

Therefore share of each of the partner

= 1/3 x 1080 = Rs. 360

Question 2 |

If Rs. 1066 are divided among A,B,C Â and D such that A:B =3:4,B:C=5:6 and C:D = 7:5, who will get the maximum ?

B | |

A | |

C | |

D |

Question 2 Explanation:

Given ratios are A/B = Â¾
B/C = 5/6
C/D = 7/5
A/BÂ = 3 X 5 /4 X 5 = 15/20
B/C = 5 X 4 /6 X 4 = 20/24
B/C = 20 X 7/ 24 X 7 = 140/168
C/D = 7 X 24 / 5 X 24 = 168/120
A/B = 15 X 7 /20 X 7 = 105/140
That means A:B:C:D= 105 : 140 : 168 : 120
Hence C gets the maximum share

Question 3 |

The monthly income of the two people is in the ratio of 4:5 and their monthly expenditures are in the ratio of 7: 9 .If each saves Rs. 50 a month, then what are their incomes ?

Rs. 100, Rs. 125 | |

Rs. 200, Rs. 250 | |

Rs. 300, Rs. 375 | |

Rs. 400, Rs. 500 |

Question 3 Explanation:

Ratio of the income = 4:5

And the ratio of expenses = 7:9

Let the income = Rs. P

The incomes = 4p and 5p

Let the expenses = q

So expenses = 7q and 9q

Therefore from the given conditions

4p â€“ 7q = 50

5p â€“ 9q = 50

By solving these two equations, we get:

p= 100 and q = Rs. 50

Therefore the income of two persons = Rs. 400 and Rs. 500

And the ratio of expenses = 7:9

Let the income = Rs. P

The incomes = 4p and 5p

Let the expenses = q

So expenses = 7q and 9q

Therefore from the given conditions

4p â€“ 7q = 50

5p â€“ 9q = 50

By solving these two equations, we get:

p= 100 and q = Rs. 50

Therefore the income of two persons = Rs. 400 and Rs. 500

Question 4 |

A sum of Rs. 370 is to be divided among Prashant(P), Maninder(M), Atish(A)Â such that Pâ€™s share/ Mâ€™s share = Mâ€™s share/ Aâ€™s share = Â¾ . Then Pâ€™s share is ___ ?

Rs. 240 | |

Rs. 120 | |

Rs. 100 | |

Rs. 90 |

Question 4 Explanation:

Pâ€™s share/ Mâ€™s share = (3 x 3)/(4 x 3)= 9/12

Mâ€™s share/ Aâ€™s share = 3 x 4/ 4 x 4 = 12/16

Therefore A : B : C = 9 : 12 : 16

Therefore Prashantsâ€™ share = 9/37 x 370 = Rs 90

Mâ€™s share/ Aâ€™s share = 3 x 4/ 4 x 4 = 12/16

Therefore A : B : C = 9 : 12 : 16

Therefore Prashantsâ€™ share = 9/37 x 370 = Rs 90

Question 5 |

A man divided Rs. 770 among Richa, Natasha, Sona such that Richa receives 2/9

^{th}of what Natasha and Sona together receive. Then Richaâ€™s share is___ ?Rs. 140 | |

Rs. 154 | |

Rs.Â 165 | |

Rs. 170 |

Question 5 Explanation:

Total amount of money = 770

Richa share = 2/9(Natasha + Sona)

From the above equations, we get

Richa + 9/2 Richa = 770

11Richa = 770 x 2

Richa = 140

Therefore Richaâ€™s share = Rs. 140

Richa share = 2/9(Natasha + Sona)

From the above equations, we get

Richa + 9/2 Richa = 770

11Richa = 770 x 2

Richa = 140

Therefore Richaâ€™s share = Rs. 140

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