• This is an assessment test.
  • These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
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Basic Maths: Test 11

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Question 1
The value of $ \displaystyle 1+\frac{3}{1+\frac{2}{3+\frac{4}{5}}}$
A
$ \displaystyle \frac{12}{29}$
B
$ \displaystyle \frac{68}{19}$
C
$ \displaystyle \frac{86}{29}$
D
$ \displaystyle \frac{2}{19}$
Question 1 Explanation:
$ \displaystyle \begin{array}{l}1+\frac{3}{1+\frac{2}{\frac{15+4}{5}}}\\=1+\frac{3}{1+\frac{2\times 5}{19}}\\=1+\frac{3}{\frac{19+10}{19}}\\=1+\frac{57}{29}=\frac{29+57}{29}=\frac{86}{29}\end{array}$
Question 2
Simplify $ \displaystyle \frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{1}{1+\frac{1}{4}}}}$
A
$ \displaystyle \frac{19}{43}$
B
$ \displaystyle \text{1}$
C
$ \displaystyle \frac{34}{19}$
D
$ \displaystyle \frac{45}{43}$
Question 2 Explanation:
We can simplified this question as
$ \displaystyle \begin{array}{l}\frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{1}{1+\frac{1}{4}}}}\\=\frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{4}{5}}}\\=\frac{19}{43}\div \frac{1}{2+\frac{5}{19}}\\=\frac{19}{43}\div \frac{19}{43}\\=\frac{19}{43}\times \frac{43}{19}=1\end{array}$
So the right answer for the question is option b
Question 3
The simplification of $ \displaystyle \frac{4}{3+\frac{3}{1-\frac{2}{3}}}$ gives
A
7
B
1/3
C
5/12
D
7/12
Question 3 Explanation:
We can simplified the equation as
$ \displaystyle \begin{array}{l}\frac{4}{3+\frac{3}{\frac{3-2}{3}}}\\=\frac{4}{3+\frac{3}{\frac{1}{3}}}\\\frac{4}{3+3\times 3}\\=\frac{4}{3+9}\\=\frac{4}{12}\\=\frac{1}{3}\end{array}$
So the best option for the question is option b
Question 4
$ \displaystyle 8=p+\frac{1}{1+\frac{1}{3+\frac{1}{4}}}$, then the value of p is:
A
$ \displaystyle \frac{191}{17}$
B
$ \displaystyle \frac{123}{17}$
C
$ \displaystyle \frac{141}{17}$
D
$ \displaystyle \frac{133}{17}$
Question 4 Explanation:
$ \displaystyle \begin{array}{l}8=p+\frac{1}{1+\frac{1}{3+\frac{1}{4}}}\\\Rightarrow 8=p+\frac{1}{1+\frac{1}{\frac{12+1}{4}}}\\\Rightarrow 8=p+\frac{1}{1+\frac{4}{13}}\\\Rightarrow 8=p+\frac{1}{\frac{13+4}{13}}\\\Rightarrow 8=p+\frac{1}{\frac{17}{13}}\\\Rightarrow 8=p+\frac{13}{17}\,\,\\\Rightarrow \,p=8-\frac{13}{17}\\=\frac{123}{17}\end{array}$
Question 5
basic-maths-test-11-1
A
$ \displaystyle \frac{12}{29}$
B
$ \displaystyle \frac{68}{19}$
C
$ \displaystyle \frac{86}{29}$
D
$ \frac{2}{19}$
Question 5 Explanation:
basic-maths-test-11-answer-1
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