- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 39

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Question 1 |

The simplification of $\frac{4.8\times 64+4.8\times 36}{{{\left( 7.4 \right)}^{2}}-{{\left( 2.6 \right)}^{2}}}$ yields the result

7.2 | |

8.5 | |

10 | |

12 |

Question 1 Explanation:

Expression

$\begin{align} & \frac{4.8\left( 64+36 \right)}{\left( 7.4+2.6 \right)\left( 7.4-2.6 \right)} \\ & =\frac{4.8\times 100}{10\times 4.8}=10 \\ \end{align}$

$\begin{align} & \frac{4.8\left( 64+36 \right)}{\left( 7.4+2.6 \right)\left( 7.4-2.6 \right)} \\ & =\frac{4.8\times 100}{10\times 4.8}=10 \\ \end{align}$

Question 2 |

$\left( 0.3\times 0.4+0.02 \right){{\left( 0.5\times 0.1+0.09 \right)}^{-1}}$ is equal to

1 | |

$\frac{41}{12}$ | |

$\frac{41}{4}$ | |

$\frac{9}{5}$ |

Question 2 Explanation:

Expression

$\begin{align} & =\frac{\left( 0.12+0.02 \right)}{\left( 0.05+0.09 \right)} \\ & =\frac{0.14}{0.14}=1 \\ \end{align}$

$\begin{align} & =\frac{\left( 0.12+0.02 \right)}{\left( 0.05+0.09 \right)} \\ & =\frac{0.14}{0.14}=1 \\ \end{align}$

Question 3 |

$5\frac{1}{5}-2\frac{1}{9}=?-7\frac{3}{5}-3\frac{1}{2}$

$13\frac{5}{63}$ | |

$13\frac{107}{126}$ | |

$14\frac{19}{90}$ | |

$14\frac{17}{90}$ |

Question 3 Explanation:

$\begin{align}
& 5\frac{1}{5}-2\frac{1}{9}=?-7\frac{3}{5}-3\frac{1}{2} \\
& \Rightarrow 5+\frac{1}{5}-2-\frac{1}{9}=?-7-\frac{3}{5}-3-\frac{1}{2} \\
& \Rightarrow ?=5+\frac{1}{5}-2-\frac{1}{9}+7+\frac{3}{5}+3+\frac{1}{2} \\
& =13+\left( \frac{1}{5}-\frac{1}{9}+\frac{3}{5}+\frac{1}{2} \right) \\
& =13+\left( \frac{18-10+54+45}{90} \right) \\
& =13+\frac{107}{90}=13+1\frac{17}{90} \\
& =14\frac{17}{90} \\
\end{align}$

Question 4 |

$\left( 0.125 \right)\div {{\left( 0.25 \right)}^{3}}\times \left( 0.0625 \right)={{\left( 0.5 \right)}^{?+1}}$

0 | |

1 | |

â€“1 | |

â€“2 |

Question 4 Explanation:

Question 5 |

The value of
$\frac{{{\left( 5.123 \right)}^{3}}+{{\left( 3.456 \right)}^{3}}-{{\left( 8.579 \right)}^{3}}}{\left( 5.123 \right)\,\left( 3.456 \right)\,\left( -8.579 \right)}$
lies between

â€“0.5 and 0 | |

0 and 0.5 | |

0.5 and 1 | |

2.5 and 3.5 |

Question 5 Explanation:

$\begin{align}
& If\,\,\,a+b+c=0,\,\,then\,\,\,{{a}^{3}}+{{b}^{3}}+{{c}^{3}}=3abc \\
& Here,\,\,\,\,5.123+3.456-8.579=0 \\
& Expression\, \\
& =\frac{3\times \left( 5.123 \right)\left( 3.456 \right)\left( -8.579 \right)}{\left( 5.123 \right)\left( 3.456 \right)\left( -8.579 \right)}=3 \\
\end{align}$

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