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Basic Maths: Test 46

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Question 1
$\left[ \frac{{{\left( 0.54 \right)}^{3}}+{{\left( 0.45 \right)}^{3}}}{{{\left( 0.54 \right)}^{2}}+{{\left( 0.45 \right)}^{2}}-\left( 0.54 \right)\times \left( 0.45 \right)} \right]$ Simplifies to:
A
1
B
0.4087
C
0.73
D
0.27
Question 1 Explanation:
Let 0.54= a and 0.45 = b
Therefore expression
$\begin{align} & =\frac{{{a}^{3}}+{{b}^{3}}}{{{a}^{2}}+{{b}^{2}}-ab} \\ & =\frac{\left( a+b \right)\left( {{a}^{2}}+{{b}^{2}}-ab \right)}{{{a}^{2}}+{{b}^{2}}-ab} \\ & =a+b=0.54+0.45=1 \\ \end{align}$
Question 2
$\left( 79\times 21+25\times 17+7\times 3 \right)$ equals
A
2450
B
2405
C
2150
D
2105
Question 2 Explanation:
Expression
$\begin{align} & =\left( 79\times 21+25\times 17+7\times 3 \right) \\ & =1659+425+21=2105 \\ \end{align}$
Question 3
$\left( 0.06\times 6-0.006\times 6 \right)$ is equal to:
A
3.240
B
0.366
C
0.324
D
0.342
Question 3 Explanation:
Expression
$\begin{align} & =0.06\times 6-0.006\times 6 \\ & =0.36-0.036=0.324 \\ \end{align}$
Question 4
The value of $\sqrt[3]{\frac{0.3\times 0.3\times 0.3+0.05\times 0.05\times 0.05}{0.6\times 0.6\times 0.6+0.1\times 0.1\times 0.1}}$ is
A
0.5
B
0.25
C
0.75
D
0.125
Question 4 Explanation:
Let 0.3= a and 0.05= b
Therefore 0.6 = 2a and 0.1 = 2b
Therefore expression
6
Question 5
$\frac{{{\left( 2.25 \right)}^{\frac{1}{2}}}\times {{\left( 0.0196 \right)}^{\frac{1}{2}}}+1-0.01}{{{\left( 0.064 \right)}^{\frac{1}{3}}}\times {{\left( 16 \right)}^{\frac{1}{4}}}}$ is simplified to
A
0.15
B
1.5
C
1
D
$1.\overline{5}$
Question 5 Explanation:
Expression
$\begin{align} & =\frac{{{\left( 2.25 \right)}^{\frac{1}{2}}}\times {{\left( 0.0196 \right)}^{\frac{1}{2}}}+1-0.01}{{{\left( 0.064 \right)}^{\frac{1}{3}}}\times {{\left( 16 \right)}^{\frac{1}{4}}}} \\ & =\frac{{{\left( 1.5 \right)}^{2\times \frac{1}{2}}}\times {{\left( 0.14 \right)}^{2\times \frac{1}{2}}}+1-0.01}{{{\left( 0.4 \right)}^{3\times \frac{1}{3}}}\times {{\left( 2 \right)}^{4\times \frac{1}{4}}}} \\ & =\frac{1.5\times 0.14+1-0.01}{0.4\times 2}=\frac{0.21+1-0.01}{0.8} \\ & =\frac{1.20}{0.8}=\frac{120}{80} \\ & =1.5 \\ \end{align}$
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