- This is an assessment test.
- To draw maximum benefit, study the concepts for the topic concerned.
- Kindly take the tests in this series with a pre-defined schedule.

## Geometry and Mensuration: Level 1 Test 9

Start

Congratulations - you have completed

*Geometry and Mensuration: Level 1 Test 9*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

The number of bricks, each measuring 25 cm x 12.5 cm x 7.5 cm, required to construct a wall 6 m long, 5 m high and 0.5 m thick, while the mortar occupies 5% of the volume of the wall, is

A | 5740 |

B | 6080 |

C | 3040 |

D | 8120 |

Question 1 Explanation:

$ \displaystyle Total\text{ }number\text{ }of\text{ }bricks\text{ }required\text{ }=\frac{600\times 500\times 50\times 0.95}{25\times 12.5\times 7.5}=6080$

Question 2 |

A and B travel around a circular path at uniform speeds in opposite directions, starting from diametrically opposite points, at the same time. They meet each other first after B has travelled 100 metres and meet again 60 metres before A completed one round. The circumference of the park is

A | 240 m |

B | 300 m |

C | 320 m |

D | 480 m |

Question 2 Explanation:

Let A travel x m in the first meeting and thus the ratio of speeds of A and B is x/100.

Total circumference = 2(x+100) as they were diametrically opposite.

In the 2

B has travelled = 100+x+60 = 160+x,

Ratio of speed A:B = 2x+140/160+x

Equating the two ratios we will get,

x= 140.

Thus the circumference = 2X140+200 = 480 m

Total circumference = 2(x+100) as they were diametrically opposite.

In the 2

^{nd}meeting A has travelled 2x+200-60 = 2x+140.B has travelled = 100+x+60 = 160+x,

Ratio of speed A:B = 2x+140/160+x

Equating the two ratios we will get,

x= 140.

Thus the circumference = 2X140+200 = 480 m

Question 3 |

If the radius of circle is increased by 50%, then the area of the circle is increased by

A | 125% |

B | 100% |

C | 75% |

D | 50% |

Question 3 Explanation:

Area is directly proportional to r

=> Area is directly proportional to (1.5 r

=> Area is directly proportional to 2.25r

The area has increased by (2.25 -1)x100 = 125%

^{2}=> Area is directly proportional to (1.5 r

^{2})=> Area is directly proportional to 2.25r

The area has increased by (2.25 -1)x100 = 125%

Question 4 |

Four sheets 50 cm x 5 cm are arranged without overlapping to form a square having side 55 cm. What is the area of inner square so formed?

A | 2500 cm ^{2} |

B | 2025 cm ^{2} |

C | 1600 cm ^{2} |

D | None of these |

Question 4 Explanation:

The side of the inner square = 55 – 2 x 5 = 45 cm = 55 -2X5 = 45 cm.

The area of the inner square = 45

The area of the inner square = 45

^{2}=2025 cm^{2}Question 5 |

A photo measures 0.9 x cm by 0.94 x cm. It is to be enlarged so that the larger dimension will be 6 cm. The length of the enlarged shorter dimension will be

A | 5.74x cm |

B | 5.4x cm |

C | 5.64x cm |

D | 7.09x cm |

Question 5 Explanation:

$latex \displaystyle The\text{ }required\text{ }length=\frac{0.9\times 6}{0.94}=5.74$

Once you are finished, click the button below. Any items you have not completed will be marked incorrect. Get Results

There are 5 questions to complete.

← | List | → |

Return

Shaded items are complete.

1 | 2 | 3 | 4 | 5 |

End |

Return

You have completed

questions

question

Your score is

Correct

Wrong

Partial-Credit

You have not finished your quiz. If you leave this page, your progress will be lost.

Correct Answer

You Selected

Not Attempted

Final Score on Quiz

Attempted Questions Correct

Attempted Questions Wrong

Questions Not Attempted

Total Questions on Quiz

Question Details

Results

Date

Score

Hint

Time allowed

minutes

seconds

Time used

Answer Choice(s) Selected

Question Text

All done

Need more practice!

Keep trying!

Not bad!

Good work!

Perfect!