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Arithmetic: Profit and Loss Test -2

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Question 1
Postcards costing 30 paise each and inland letters costing Rs 1.50 each were purchased for Rs. 66. Total number of postcards and inland letters purchased was 60. If the number of postcards and inland letters is interchanged, then the cost is:
A
Rs 42
B
Rs 30
C
Rs 21
D
Rs 60
Question 1 Explanation:
Let us assume the number of postcards = n
Let the assume the number of letters   = m
Therefore,
0.30 x n + 1.50 x m = 66………………………i
n +m=60 ...............................................ii
On solving equation i and ii
We get n = 20, and m= 40
Therefore, the required cost price
= 0.30 x40 +1.5 x 20
= 12 + 30 =Rs 42
Question 2
Maninder bought a certain number of pen drives for for 1800.  Keeping one to himself, he sold the rest at a profit of Rs 6 each. In total, he earned a profit of Rs. 114. The number of pen drives he bought are:
A
20
B
28
C
32
D
30
Question 2 Explanation:
Let Maninder buy (A) number of pen drives
So
(A-1) x 6=114
A-1 = 19
A=20
Question 3
A garment company declared 15% discount for wholesale buyers. Bharat bought garments from the company for Rs. 25000 after getting a discount. He fixed up the selling price of garments in such a way that he earned a profit of 8% on original company price. What is the approximate total selling price?
A
Rs 28000
B
Rs 29000
C
Rs 32000
D
Rs 29500
Question 3 Explanation:
Given cost price of garments = Rs25000 Company price = 25000/85 x 100 Profit = 8% Therefore Bharat sold the Garments = 25000/85 x 100 x 108/100 = Rs 31764.71 = Rs. 32000
Question 4
A shopkeeper sold an article at a profit of 17.5%. If he had bought it at 8% less and sold it at 30% profit, he would have earned Rs. 11.55 more as profit. Cost price of the article is:
A
Rs 550
B
Rs 675
C
Rs 750
D
Rs 1475
Question 4 Explanation:
Let the cost price of the article be Rs (P)
So according to question
Selling price = P x (117.5)/100
If he had bought it at 8% less and sold it at 30% profit, he would have earned Rs. 11.55 more as profit.
Therefore P x (117.5)/100 + 11.55
= P x (92/100) x130/100
P = (11.55)/(0.99 x 130 -117.5) x 100
P= Rs 550
Question 5
A manufacturer sold a machine to a wholesale dealer at a profit of 10%. The wholesale dealer sold it to a retailer at a profit of 20%. While transporting some defect occurred in the machine and hence the retailer sold it at a loss of 5%. The customer paid Rs672. Find the cost of the machine for the manufacturer.
A
Rs 672
B
Rs 500
C
Rs 572
D
None
Question 5 Explanation:
This is a very simple problem.
Let cost price of the machine  = p
p x (110/100) x (120/100) x (95/100) = 672
p=535.88
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Table of Contents: Profit and Loss Complete Lesson