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• This is an assessment test.
• These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
• Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 26

Congratulations - you have completed Basic Maths: Test 26.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
 Question 1
$\displaystyle 402.46+495.72-423.47=?$
 A 576.77 B 547.17 C 547.77 D 474.71
Question 1 Explanation:
$\displaystyle \begin{array}{l}402.46+495.72-423.47=?\\=898.18-423.47=474.71\end{array}$
 Question 2
$\sqrt[3]{5832}\div \sqrt[3]{216}=\sqrt[3]{?}$
 A 16 B 8 C 27 D 4
Question 2 Explanation:
$\displaystyle \begin{array}{l}\sqrt[3]{?}=\sqrt[3]{5832}\div \sqrt[3]{216}\\=\sqrt[3]{18\times 18\times 18}\div \sqrt[3]{6\times 6\times 6}\\=18\div 6=3\\Therefore\,\,\,p=3\times 3\times 3=27\end{array}$
 Question 3
?% of 400 = 293-22% of 750
 A 24 B 32 C 22 D 26
Question 3 Explanation:
$\displaystyle \begin{array}{l}\frac{400\times ?}{100}=293-\frac{750\times 22}{100}\\\Rightarrow 4\times ?=293-165=128\\\Rightarrow ?=\frac{128}{4}=32\end{array}$
 Question 4
$\displaystyle 273\div 7-9.1=p$
what is the value of p
 A 29.9 B 22.3 C 24.9 D 21.8
Question 4 Explanation:
$\displaystyle p=\frac{273}{7}-9.1=39-9.1=29.9$
 Question 5
$\displaystyle \sqrt{3969}\div 0.7=?\times 2.5$
 A 18 B 36 C 16 D 24
Question 5 Explanation:
$\displaystyle \begin{array}{l}\sqrt{3969}\div 0.7=?\times 2.5\\\Rightarrow 63\times \frac{1}{0.7}=?\times 2.5\\\Rightarrow ?=\frac{63}{0.7\times 2.5}=36\end{array}$
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